+0  
 
+6
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avatar+1836 

1. When I swing at a nail, I drive it all the way in with probability 1/2. With probability 1/4, I hit it half-way in, and with 1/4 probability I miss it entirely. Hitting it half-way in twice will drive it all of the way in. I'm pretty sure that if I swing 4 times at a nail, I'll get it all the way in almost all the time. Let's see if I'm right. How many sequences of 4 swings could leave the nail still not knocked all the way in?

2. When I swing at a nail, I drive it all the way in with probability 1/2. With probability 1/4, I hit it half-way in, and with 1/4 probability I miss it entirely. I'm pretty sure that if I swing 4 times at a nail, I'll get it all the way in almost all the time. Let's see if I'm right. What is the probability I fail to get the nail driven completely in?

 Apr 8, 2015

Best Answer 

 #1
avatar+33661 
+22

1. There are 5 sequences of four swings that would fail to get the nail knocked all the way in. They are:

(miss miss miss miss)                                 prob = (1/4)4

(halfway miss miss miss)                            prob = (1/4)4

(miss halfway miss miss)                            prob = (1/4)4

(miss miss halfway miss)                            prob = (1/4)4

(miss miss miss halfway)                            prob = (1/4)4

 

2.  Overall probability = 5*(1/4)4 = 5/256 

.

 Apr 8, 2015
 #1
avatar+33661 
+22
Best Answer

1. There are 5 sequences of four swings that would fail to get the nail knocked all the way in. They are:

(miss miss miss miss)                                 prob = (1/4)4

(halfway miss miss miss)                            prob = (1/4)4

(miss halfway miss miss)                            prob = (1/4)4

(miss miss halfway miss)                            prob = (1/4)4

(miss miss miss halfway)                            prob = (1/4)4

 

2.  Overall probability = 5*(1/4)4 = 5/256 

.

Alan Apr 8, 2015
 #2
avatar+118723 
+8

Welcome to the forum Mellie    

 Apr 9, 2015
 #3
avatar+1836 
+7

Thanks Melody! 

 Apr 9, 2015

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