+79 1. Solve for x and y:
|x|+x+y=14
x+|y|-y=12
2.All the roots of the cubic polynomial f(x)=3x^3+bx^2+c+d are negative real numbers. If f(0)=81, find the smallest possible value of f(1). Prove that your answer is the minimum
3.Let f(x) be an even function, and let g(x) be an odd function, such that f(x)+g(x)=x^2+2^x for all real numbers x. Find f(2)
+2401 |x|+x+y=14
x+|y|-y=12
Both x and y are positive.
2x + y = 14
x = 12
y = -10
WRONG (since -10 isn't positive)
x is positive and y is negative
2x + y = 14
x - 2y = 12
4x + 2y = 28
5x = 40
x = 8, y = -2
CORRECT
=^._.^=
+874 (2) $c+d=81$
$f(1) = 3 + b + c + d = 3 + b + 81 = 84 + b.$ $b$ is at least $1$ so the answer is $84+1=\boxed{85}$
