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1. What is the exact value of sin 60dg? Answer as a fraction in simplest form.

 

2. What is the area of this triangle? Round final answer to the nearest tenth.

Guest Apr 17, 2017
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1. \(\sin 60^{\circ} = \dfrac{\sqrt 3}{2}\)

2. Area of the triangle = \(\dfrac{1}{2}\cdot 12\cdot 8 \cdot \sin65^{\circ}\\ =48 \sin 65^{\circ}\\\approx 43.5\text{cm}^2\)

MaxWong  Apr 17, 2017

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