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(1+x^2)i/(1+xi)+(x-6i)

 Sep 24, 2017
 #1
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(1 + x2)i/(1 + xi) + x- 6i → (1 + x2)i(1 - xi)/((1 + xi)(1 - xi)) + x - 6i

 

→ (1 + x2)i(1 - xi)/(1 + x2) + x - 6i → 1 - xi + x - 6i 

 

→ 1 + x - (x + 6)i 

 Sep 24, 2017

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