((10*10^6)/1024)*((768*log(16))/1.125)
can u translate to Mbps this number?
my teacher say the result is 24 Mbps
If we assume the 106 accounts for the M (Mega), and note that log2(16) = 4, then we have:
R = (10/1024)*(768*4/1.125) → 7680/(256*1.125) → 80/3 → 26.7 Mbps
.
However, if the 0.125 in the denominator were to be 0.25 instead, then the result would be 24 Mbps.
=26,666,666.67=26.67 x 10^6 Mbps
