10^2=x^2+(x+2)^2

$$\\10^2=x^2+(x+2)^2\\
100=x^2+x^2+4x+4\\
0=2x^2+4x-96\\
0=x^2+2x-48\\
0=(x-6)(x+8)\\
x=6\quador \quad x=-8$$

.

$${{\mathtt{10}}}^{{\mathtt{2}}} = {{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)}^{{\mathtt{2}}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{6}}\\
{\mathtt{x}} = -{\mathtt{8}}\\
\end{array} \right\}$$

.