10-(2y-6)-y=?. You have to set your equation to equal 0, like this:
Solve for y:
16-3 y=0
Subtract 16 from both sides:
(16-16)-3 y=-16
16-16=0:
-3 y=-16
Divide both sides of -3 y=-16 by -3:
(-3 y)/(-3)=(-16)/(-3)
(-3)/(-3)=1:
y=(-16)/(-3)
The sign of (-16)/(-3) is positive, so (-16)/(-3) = 1×16/3:
Answer: | y=16/3
