10+4-[3-{1+2-(4-9)}]

Question

0

775

2

Guest Apr 20, 2014

+118677

+5

Best Answer

Start with the inner most brackets and work your way out.

$$10+4-(3-(1+2-(4-9)))\\
=14-(3-(3-(-5)))\\
=14-(3-(3--5))\\
=14-(3-(8))\\
=14-(3-8)\\
=14--5\\
=14+5\\
=19$$

Melody Apr 21, 2014

Melody · Answer 1 · 2014-04-21T11:30:14

Start with the inner most brackets and work your way out.

$$10+4-(3-(1+2-(4-9)))\\
=14-(3-(3-(-5)))\\
=14-(3-(3--5))\\
=14-(3-(8))\\
=14-(3-8)\\
=14--5\\
=14+5\\
=19$$

BlindxD · Answer 2 · 2014-04-20T05:01:58

why wont you just check it in the calculater? its 19