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10*log10(1/1+x2)= 3

 

how to solve x?

Guest Mar 1, 2017
 #1
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Can you show me how to solve for x?

Guest Mar 1, 2017
 #2
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I assume this is :

 

10*log10(1/[1+x^2])= 3      divide each side by 10

 

log10 ( 1 / [ 1 + x^2] )  = 3/10  

 

In exponential form, this says that

 

10^(3/10)  =   1 / [ 1 + x^2]     and we can write

 

1 + x^2   =   1 / 10^(3/10)     subtract 1 from both sides

 

x^2 = 1 / 10^(3/10) -1         take  both pos/neg square roots  and we have that

 

x = ±√ [1 / 10^(3/10) -1 ]  ≈   ± .706 i    [a non-real solution ]

 

 

cool cool cool

CPhill  Mar 1, 2017

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