10√​x​​​+3=2√​x​​​+2

10√​x​​​+3=2√​x​​​+2

$$\\10\sqrt{x}+3=2\sqrt{x}+2\\\\ 8\sqrt{x}+3=+2\\\\ 8\sqrt{x}=-1\\\\ \sqrt{x}=\frac{-1}{8}\\\\$$

If the square root is in the question then it is defined to be positive.

So there is no solution to this.   

is that $${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}$$ or $${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}}}$$ ?