10 years ago Mrs.Smith’s age was 17 times her daughter Angela’s age. 6 years later, Mrs.Smith’s age would be 4 years less than three times A

Question

10 years ago Mrs.Smith’s age was 17 times her daughter Angela’s age. 6 years later, Mrs.Smith’s age would be 4 years less than three times A

0

562

3

10 years ago Mrs.Smith’s age was 17 times her daughter Angela’s age. 6 years later, Mrs.Smith’s age would be 4 years less than three times Angela’s age. Assuming Mrs. Smith’s present age as x years and Angela’s age as y years, frame two linear equations to model this situation.

Guest Dec 18, 2020

0 users composing answers..

3⁺⁰ Answers

0 Online Users

Guest · Answer 1 · 2020-12-18T03:06:21

#1

0

(x-10) = 17y

(x-4)+4 = 3y

Guest Dec 18, 2020

#2

0

If you solve the 2 equations, this is what you get:

x = -15/7 and y = -5/7 [Hmm......Funny ages for mother and daughter !!! ]

Guest Dec 18, 2020

#3

+1

yep...I made a mistake...thanx!

(x-10) = 17(y-10)

(x-4)+4 = 3(y-4) Sorry ! But I think the question has an error in it .

I question the '17' number

Let's say it was SUPPOSED to be 7

(x-10) = 7(y-10)

(x-4)+4 = 3(y-4) then y = 12 x = 24

Guest Dec 18, 2020

10 years ago Mrs.Smith’s age was 17 times her daughter Angela’s age. 6 years later, Mrs.Smith’s age would be 4 years less than three times A

0 users composing answers..

3⁺⁰ Answers

0 Online Users

Top Users

Sticky Topics

10 years ago Mrs.Smith’s age was 17 times her daughter Angela’s age. 6 years later, Mrs.Smith’s age would be 4 years less than three times A

0 users composing answers..

3+0 Answers

0 Online Users

Top Users

Sticky Topics

3⁺⁰ Answers