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100 g CaCO3 x (1 mol CaCO3/100.09 g CaCO3) x (1 mol CaO/1 mol CaCO3) x (56.08 g CaO/1 mol CaO)
 Oct 23, 2013
 #1
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http://www.mymathforum.com/index.php

I can't answer this, if I could, I would.
If you do not get an answer soon you may consider posting your question in the forum above.
I think you will be more likely to get an answer there.
There is a section there specifically for physics and chemistry questions.
 Oct 24, 2013

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