+0  
 
0
792
1
avatar+143 
100 648-05-04-00-00_files/i0060000.jpg – 40 648-05-04-00-00_files/i0060001.jpg + 4  648-05-04-00-00_files/i0060002.jpg 1

 























a.


{ 648-05-04-00-00_files/i0060003.jpg648-05-04-00-00_files/i0060004.jpg}


c.


{ 648-05-04-00-00_files/i0060005.jpg648-05-04-00-00_files/i0060006.jpg}


b.


{ 648-05-04-00-00_files/i0060007.jpg}


d.


{ 648-05-04-00-00_files/i0060008.jpg, 1}

    

 
 Dec 16, 2014

Best Answer 

 #1
avatar+129847 
+5

100x^2 - 40x + 4 = 1    subtract 1 from both sides

100x^2 - 40x + 3  = 0   factor

(10x -3)(10x -1) = 0

So, setting each factor to 0, we have

10x - 3 = 0   →  10x = 3 →    x = 3/10

10x - 1 = 0   →  10x = 1 →    x = 1/10

"a" is correct

 

 Dec 16, 2014
 #1
avatar+129847 
+5
Best Answer

100x^2 - 40x + 4 = 1    subtract 1 from both sides

100x^2 - 40x + 3  = 0   factor

(10x -3)(10x -1) = 0

So, setting each factor to 0, we have

10x - 3 = 0   →  10x = 3 →    x = 3/10

10x - 1 = 0   →  10x = 1 →    x = 1/10

"a" is correct

 

CPhill Dec 16, 2014

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