-11/4+2/3|3y-6|=-2 solve the absolute value equation

-11/4+2/3|3y-6|=-2

do you mean

$$\begin{array}{rlll}
\frac{-11}{4}+\frac{2}{3}\times |3y-6|&=&-2\qquad &\mbox{}\\\\
\frac{2}{3}\times |3y-6|&=&-2+\frac{11}{4} \qquad &\mbox{I've added 11/4 to both sides}\\\\
\frac{2}{3}\times |3y-6|&=&-2+2\frac{3}{4} \qquad &\mbox{I've simplified}\\\\
\frac{2}{3}\times |3y-6|&=&\frac{3}{4} \qquad &\mbox{I've simplified}\\\\
|3y-6|&=&\frac{3}{4}\times \frac{3}{2} \qquad &\mbox{I've mult both sides by 3/2}\\\\
|3y-6|&=&\frac{9}{8} \qquad &\mbox{I've simplified}\\\\
\end{array}$$

Now there are 2 equations to be solved.

$$3y-6=\frac{9}{8}\qquad and \qquad 3y-6=\frac{-9}{8}$$

You should be able to finish it from here.  

-11/4+2/3|3y-6|=-2 solve the absolute value equation

Add 11/4 to both sides

(2/3)l3y-6l = 3/4       multiply both sides by 3/2

l3y-6l = 9/8        So we have two equations to solve

3y-6 = 9/8     and  -(3y-6) = 9/8

For the first one, add 6 to both sides

3y = 57/8       divide by 3 on both sides

y = 19/8

For the second equation, we have (multiplying both sides by -1)

3y - 6 = -9/8     add 6 to both sides

3y = 39/8         divide both sides by 3

y = 13/8