(12^4)(3^-2)(4^-2)

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(12^4)(3^-2)(4^-2)

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(12^4)*(3^-2)*(4^-2)

Guest Nov 25, 2014

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(12^4)*(3^-2)*(4^-2)

$(12^4)*(3^{-2})*(4^{-2}) \\\\ = \dfrac{12^4}{(3^2)(4^2)} \\\\ = \dfrac{12^4}{(3*4)^2} \\\\ = \dfrac{12^4}{12^2} \\\\ = 12^{4-2} \\\\ = 12^{2} \\\\ = 144$

heureka Nov 26, 2014

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heureka · Answer 1 · 2014-11-26T05:37:56

(12^4)*(3^-2)*(4^-2)

$(12^4)*(3^{-2})*(4^{-2}) \\\\ = \dfrac{12^4}{(3^2)(4^2)} \\\\ = \dfrac{12^4}{(3*4)^2} \\\\ = \dfrac{12^4}{12^2} \\\\ = 12^{4-2} \\\\ = 12^{2} \\\\ = 144$

Tiddle · Answer 2 · 2014-11-25T06:27:12

$\left({{\mathtt{12}}}^{{\mathtt{4}}}\right){\mathtt{\,\times\,}}\left({{\mathtt{3}}}^{-{\mathtt{2}}}\right){\mathtt{\,\times\,}}\left({{\mathtt{4}}}^{-{\mathtt{2}}}\right) = {\mathtt{144}}$

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(12^4)(3^-2)(4^-2)

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