(12^4)*(3^-2)*(4^-2)
$$(12^4)*(3^{-2})*(4^{-2}) \\\\= \dfrac{12^4}{(3^2)(4^2)} \\\\= \dfrac{12^4}{(3*4)^2} \\\\= \dfrac{12^4}{12^2} \\\\= 12^{4-2} \\\\= 12^{2} \\\\= 144$$
$$\left({{\mathtt{12}}}^{{\mathtt{4}}}\right){\mathtt{\,\times\,}}\left({{\mathtt{3}}}^{-{\mathtt{2}}}\right){\mathtt{\,\times\,}}\left({{\mathtt{4}}}^{-{\mathtt{2}}}\right) = {\mathtt{144}}$$
