12\b-3=6\b+4

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914

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+146

12\b-3=6\b+4

please help i dont remember how to solve any suggestions?

snip3s Sep 29, 2014

+23252

+5

Best Answer

I would multiply each term by b to get rid of the denominators:

b(12/b) - 3(b) = b(6/b) + 4(b)

12 - 3b = 6 + 4b

Can you take it from here?

geno3141 Sep 29, 2014

geno3141 · Answer 1 · 2014-09-29T06:44:56

I would multiply each term by b to get rid of the denominators:

b(12/b) - 3(b) = b(6/b) + 4(b)

12 - 3b = 6 + 4b

Can you take it from here?