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avatar+146 

12\b-3=6\b+4

please help i dont remember how to solve any suggestions?

 Sep 29, 2014

Best Answer 

 #1
avatar+23252 
+5

I would multiply each term by  b  to get rid of the denominators:

    b(12/b)  -  3(b)   =   b(6/b)  +  4(b)

          12 - 3b   =   6  +  4b

 

Can you take it from here?

 Sep 29, 2014
 #1
avatar+23252 
+5
Best Answer

I would multiply each term by  b  to get rid of the denominators:

    b(12/b)  -  3(b)   =   b(6/b)  +  4(b)

          12 - 3b   =   6  +  4b

 

Can you take it from here?

geno3141 Sep 29, 2014

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