$${\frac{{\mathtt{125}}}{\left({\frac{{\mathtt{5}}}{{\mathtt{6}}}}\right)}}{\mathtt{\,\times\,}}\left({\mathtt{15}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right){\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{2\,925}}$$
.125 /(5/6)*(15-2*3+3/4)*2) THERE WERE TOO MANY PARENTHISES YOU SHOULD OF TRIED THIS and mr.calculator would have came up with 100 if mr.calculator is correct......just kidding...... a little......
Sorry I published accidentally.
Okay I am here now.
Zegroes, I want you to highlight the question and copy it.
now open up Maths(input=result) and past the question in there.
change the of into a * sign (the calculator does not understand of)
Press publish and hopefully it will work just fine.
$${\frac{{\mathtt{125}}}{\left({\frac{{\mathtt{5}}}{{\mathtt{6}}}}\right)}}{\mathtt{\,\times\,}}\left({\mathtt{15}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right){\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{2\,925}}$$alright i did it is this better?
Let's try this again.......we have
125 / [(5/6) ((15-(2^3 + 3/4)*2))] Working inside the parentheses in the denominator
125 / [(5/6) ((15-(8 + 3/4)*2))] =
125/[(5/6) ((15-(35/4)*2))] =
125/[(5/6) (15- (35/2))] =
125/[(5/6) (-5/2)] =
125 / (-25/12) =
-125*(12/25) = (-5 * 12)
-60
Zegroes, have another go.
You have changed the position of the brackets. Just copy and paste.
You might need to use [ctrl] [v] to paste.
change the 'of' to an * sign. Everything else stays the same!
You should get the same answer as Chris. No you shouldn't!
Chris,
You made a mistake it is 2*3 not 2^3 (6 not 8)