12x^2y=1/28*3x*h you have to solve for h and i don't know how to...
I assume this is.....
12x^2y= (1/28 )*3x*h multiply both sides by 28 and divide by 3x
[(28)(12)x^2 y ] / [3x ] = h simplify
[(28)(12)/(3)] * [ x^2 / x] * y = h
[112 x] / y = h