12ysquared(y/3+9x/y squared)4yto the 3rd-72
$$\\12y^2(\frac{y}{3}+\frac{9x}{y^2})*4y^{1/3}-72\\\\ (4y^3+108x)*4y^{1/3}-72\\\\ 4y^{1/3}(4y^3+108x)-72\\\\ 16y^{3.\dot{3}}+432xy^{0.\dot{3}}-72\\\\$$
Does anyone know the answer to this????????????
I know I don't!!!!!
