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How to slove this division having angles involved [ 14.73 Angle − 37.66◦ / 26.08 Angle 122.47◦] ?

 Jan 15, 2015

Best Answer 

 #3
avatar+33665 
+5

It might be that the numerator and denominator each represent magnitude and phase angle (electrical engineers do this a lot).  Usually this would be written as: magnitude∠phase 

 

It means

 $$magnitude\times e^{i\times phase}$$

 

To do the division you divide the magnitudes and subtract the angle in the denominator from that in the numerator:

(14.73/26.08)∠(-37.66°-122.47°)  =  0.5648∠-160.13°

 

However, the poster of the question would need to say if this is what was intended.

 Jan 15, 2015
 #1
avatar+130540 
0

This doesn't make sense to me......(anyone else ???)

 

 Jan 15, 2015
 #2
avatar
+5

How to add two angles   (-37.66deg -122.47deg)

 Jan 15, 2015
 #3
avatar+33665 
+5
Best Answer

It might be that the numerator and denominator each represent magnitude and phase angle (electrical engineers do this a lot).  Usually this would be written as: magnitude∠phase 

 

It means

 $$magnitude\times e^{i\times phase}$$

 

To do the division you divide the magnitudes and subtract the angle in the denominator from that in the numerator:

(14.73/26.08)∠(-37.66°-122.47°)  =  0.5648∠-160.13°

 

However, the poster of the question would need to say if this is what was intended.

Alan Jan 15, 2015

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