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−16x^2/1225+7x/5+2.5=0 x=?

 Oct 3, 2016
 #1
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Solve for x:
-(16 x^2)/1225+(7 x)/5+2.5 = 0

-(16 x^2)/1225+(7 x)/5+2.5 = -(16 x^2)/1225+(7 x)/5+5/2:
-(16 x^2)/1225+(7 x)/5+5/2 = 0

Multiply both sides by -1225/16:
x^2-(1715 x)/16-6125/32 = 0

Add 6125/32 to both sides:
x^2-(1715 x)/16 = 6125/32

Add 2941225/1024 to both sides:
x^2-(1715 x)/16+2941225/1024 = 3137225/1024

Write the left hand side as a square:
(x-1715/32)^2 = 3137225/1024

Take the square root of both sides:
x-1715/32 = (35 sqrt(2561))/32 or x-1715/32 = -(35 sqrt(2561))/32

Add 1715/32 to both sides:
x = 1715/32+(35 sqrt(2561))/32 or x-1715/32 = -(35 sqrt(2561))/32

Add 1715/32 to both sides:
Answer: |x = 1715/32+(35 sqrt(2561))/32      or      x = 1715/32-(35 sqrt(2561))/32

 Oct 3, 2016

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