17^b=4 , then 2^(1/b)= what?
What an unusual question. I like it
$$\\17^b=4\\\\17^b=2^2\\\\(17^b)^{1/2}=(2^2)^{1/2}\\\\(17^{b/2})=2\\\\(17^{b/2})^{1/b}=2^{1/b}\\\\17^{1/2}=2^{1/b}\\\\2^{1/b}=\sqrt{17}$$
That's very nice, Melody.......!!!
Thanks Chris :)