#18,19 Help.
√ [ 250x^16 ] / √ [2x ] =
√ [ ( 250x^16) / ( 2x) ] =
√ [ 125 x^15 ] =
√25*√5 * √x^14 * √ x =
5 * √5 * x^7 * √x =
5x^7 √ [ 5x ]
The second is just like having 3x - 6x = - 3x
So we have
33√[2a ] - 63√ [2a ] = -33√[2a ]
