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A rocket, initially at rest, is fired vertically upward with an acceleration of 12.0 m/s^2. At an altitude of 1.00 km, the rocket engine cuts off. Air friction is negligible in this problem.

A. How fast is the rocket traveling when the engine cuts off?

B. What maximum height relative to the ground does the rocket reach before it begins falling back toward the earth?

C. After free-falling, what is the rocket's velocity just before it hits the earth?

 Sep 25, 2015
 #1
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V²=U²+2AS,

WHERE V=FINAL VELOCITY

U=INITIAL VELOCITY

A=ACCELERATION

S=DISTANCE OF ACCELERATION

 

You maybe able to use this formula to solve your problem.

Hint: convert 1Km into meters.

 Sep 25, 2015
 #2
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Easy Q a is 500km per hour

 Sep 25, 2015

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