(2^2)^-2

it = 0.0625

(2^2)^-2

$(2^2)^{-2}\\ =4^{-2}\\ =\frac{\color{blue}{1} *\color{black}4^{-2}}{1}\\ =\frac{\color{blue}{1} }{1*\color{black}4^{+2}}\\ =\frac{\color{blue}{1} }{\color{black}4^{2}}\\ =\frac{\color{blue}1 }{\color{black}16}\\ $