$${{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,-\,}}{\mathtt{10}}{\mathtt{\,\times\,}}\left({\mathtt{4}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{18}}\right)\right) = {\mathtt{448}}$$
.