Solve for c:
(2 (c-18))/3 = 7
Multiply both sides of (2 (c-18))/3 = 7 by 3/2:
((3×2 (c-18))/(2))/(3) = 3/2×7
3/2×7 = (3×7)/2:
(3×2 (c-18))/(2×3) = (3×7)/2
(3×2 (c-18))/(2×3) = (2×3)/(2×3)×(c-18) = c-18:
c-18 = (3×7)/2
3×7 = 21:
Answer: |
| c-18 = 21/2
c=28 1/2
