+0  
 
0
392
2
avatar

2^3x-1=(1\8)^x

Guest Mar 4, 2015

Best Answer 

 #2
avatar+26642 
+5

If this is

 

$$2^{3x-1}=(\frac{1}{8})^x$$

 

then rewrite it as

 

$$\\2^{3x-1}=(\frac{1}{2^3})^x\\\\2^{3x-1}=(2^{-3})^x\\\\2^{3x-1}=2^{-3x}$$

 

So we must have

 

$$\\3x-1=-3x\\\\6x=1\\\\x=\frac{1}{6}$$

.

Alan  Mar 4, 2015
Sort: 

2+0 Answers

 #1
avatar+47 
0

x=8^(-x-1)*((8^x)+1)

MILAN6030  Mar 4, 2015
 #2
avatar+26642 
+5
Best Answer

If this is

 

$$2^{3x-1}=(\frac{1}{8})^x$$

 

then rewrite it as

 

$$\\2^{3x-1}=(\frac{1}{2^3})^x\\\\2^{3x-1}=(2^{-3})^x\\\\2^{3x-1}=2^{-3x}$$

 

So we must have

 

$$\\3x-1=-3x\\\\6x=1\\\\x=\frac{1}{6}$$

.

Alan  Mar 4, 2015

11 Online Users

avatar
avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details