2^4 * 3^8 = 9^n * 6^4
What's N?
How do I solve this?
This is what I got:
http://www.quickmath.com/#c=simplify_algstepssimplify&v187=2%5E4*3%5E8%3D9%5En*6%5E4&v188=n
2^4 * 3^4 * 3^4 = (3^2)^n * 6^4
[ 2 * 3]^4 * 3^4 = (3^2)^n * 6^4
[ 6]^4 * 3^4 = (3^2)^n * 6^4 divide by 6^4
3^4 = (3)^(2n) solve for the exponents
4 = 2n → n = 2