+130511 Oh, OK....this is a litttle different....
2^(4x-1)=7 take the log of each side
log 2 ^(4x - 1) = log 7 and we can write
(4x - 1) log 2 = log 7 divide both sides by log 2
4x - 1 = log 7 / log 2 add 1 to both sides
4x = (log 7 / log 2 ) + 1 divide both sides by 4
x = [( log 7 / log 2 ) + 1 ] / 4 = about .9518
+130511 Oh, OK....this is a litttle different....
2^(4x-1)=7 take the log of each side
log 2 ^(4x - 1) = log 7 and we can write
(4x - 1) log 2 = log 7 divide both sides by log 2
4x - 1 = log 7 / log 2 add 1 to both sides
4x = (log 7 / log 2 ) + 1 divide both sides by 4
x = [( log 7 / log 2 ) + 1 ] / 4 = about .9518
