(2^5*3^-2)/(2^7*3^-4) = ?

(2^5*3^-2)/(2^7*3^-4) =

 

\(\frac{2^5*3^{-2}}{2^7*3^{-4}}\\ =\frac{1*3^{-2-\;-4}}{2^{7-5}}\\ =\frac{3^{-2+4}}{2^{2}}\\ =\frac{3^{2}}{2^{2}}\\ =\frac{9}{4}\\ =2\frac{1}{4}\)