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I have to put a football and a basketball into a rectangular box without deflating them and I have to use the formula 2(L x W) + 2(W x H) + 2(L x H).please help im lost

the sizes are this basketball 9.5 all around

football is 11.5 long

height of box is 6.5 inches high.

this is what im looking at.

Your goal is to construct a rectangular box with a top on it that has the smallest possible surface area, in which a football and a basketball, both fully inflated, will just fit into at the same time. Below are the measurements of the football and basketball.

Guest Jul 25, 2017
edited by Guest  Jul 25, 2017
edited by Guest  Jul 26, 2017
 #1
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If the diameter of the basketball is 9.5 inches, this means that its "width," "length" and "height" are all 9.5 inches.......therefore...it won't fit into a box that is only 6.5 inches in height

 

cool cool cool

CPhill  Jul 26, 2017

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