My math teacher needs me to show my work every step of the way for this problem. Please help (I have the graph alrdy from online calculator, but it doesn't show the math steps in order to achieve it).
x^2+9x+18 =
+118613 My math teacher needs me to show my work every step of the way for this problem. Please help (I have the graph alrdy from online calculator, but it doesn't show the math steps in order to achieve it).
x^2+9x+18 =
This is not something that can be graphed. It is just a queadratic expression.
You most likely mean
y=x^2+9x+18
Now there are different ways to takle this but I will assume that you have not done calculus.
Method:
1. You should rcognise instantly that this is a parabola. It is concave up because the number in front of X^2 is an invisable +1 A positive x^2 coefficient means it is concave up.
2. Find the y intercept. That is very easy. It is where x=0
*Now look for the roots and the axis of symmetry.
3.Factorize the Right hand side.
4. Find the roots (or zeros) That means find the x values when y=0
5. Plot these 2 points.
6. The axis of symmetry is the vertical line half way between the roots.
7. Find the y value for the vertex and plot it.
8. Sketch the graph.
Now give it a go for yourself and ask if you have problems.
+118613 My math teacher needs me to show my work every step of the way for this problem. Please help (I have the graph alrdy from online calculator, but it doesn't show the math steps in order to achieve it).
x^2+9x+18 =
This is not something that can be graphed. It is just a queadratic expression.
You most likely mean
y=x^2+9x+18
Now there are different ways to takle this but I will assume that you have not done calculus.
Method:
1. You should rcognise instantly that this is a parabola. It is concave up because the number in front of X^2 is an invisable +1 A positive x^2 coefficient means it is concave up.
2. Find the y intercept. That is very easy. It is where x=0
*Now look for the roots and the axis of symmetry.
3.Factorize the Right hand side.
4. Find the roots (or zeros) That means find the x values when y=0
5. Plot these 2 points.
6. The axis of symmetry is the vertical line half way between the roots.
7. Find the y value for the vertex and plot it.
8. Sketch the graph.
Now give it a go for yourself and ask if you have problems.
Hi, thank you for responding, I'm stuck here and I can't get ahold of my math teacher at this time. so, it is actually this:
1. Determine where f(x) intersects the x-axis.
f(x)=x^2+9x+18
(I tried just factoring it out but it resulted in '0')
+128731 1. Determine where f(x) intersects the x-axis.
f(x)=x^2+9x+18
Mmmmm.....that's quite a different question from what we assumed your original was.....!!!!!
We can write this as
y = x^2 + 9x + 18
And where it crosses the x axis, "y" will = 0 ... so we have
x^2 + 9x + 18 = 0 factor
(x + 6) ( x +3) = 0 and setting each factor to 0, we have that x = - 6 and x = -3
And those are the two points of intersection on the x axis.
