+128474 The first one is made a ittle easier by factoring a 2 out of (2x + 2) = 2(x + 1)
Now....divide each coefficient of the dividend by 2 and we get
x^5 - 3x^4 - 8x^3 - 3x^2 + 10x + 10
And we are dividing this by (x + 1)....so we have
x^4 -4x^3 -4x^2 + 1x + 9
x + 1 [ x^5 - 3x^4 - 8x^3 - 3x^2 + 10x + 10 ]
-(x^4 + 1x^4)
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-4x^4 - 8x^3
-(-4x^4 - 4x^3)
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-4x^3 - 3x^2
-(-4x^3 -4x^2)
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1x^2 + 10x
-(1x^2 + 1x)
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9x + 10
-(9x + 9)
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1
The residual polynomial is x^4 -4x^3 -4x^2 + 1x + 9 R [1/ (x + 1) ]
+128474 n^3 - 8n^2 + 6n + 9
10n + 2 [ 10n^4 - 78n^3 + 44n^2 + 102n + 26 ]
-(10n^4 + 2n^3)
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-80n^3 + 44n^2
-( -80n^3 - 16n^2)
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60n^2 + 102n
-(60n^2 + 12n)
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90n + 26
-(90n + 18)
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8
n^3 - 8n^2 + 6n + 9 R [ 8 / (10n + 2) ]
