Find the area of triangle ABC:
AB=19, ∠B= 32°.
A line is drawn from C down to AB. We call the point of intersection D.
AD= 5, ∠ACD=10°.
I don't know how to set up the equations to find x and y. Help is much appreciate
+89 you would youse the phyagorean therom, you would take the first tryangel and cut it in half know you have a right tryangel with the hypotnuse of 19 19/2 is one leg the other is 9.5 sq -19 sq do this with the second tryangel
