Dear sir, if the question given like this, 2^n=187072209578355573530071658587684226515959365500928,Find the n value ? Is there any method to find the n value within few seconds?

Suppose if the multiplication given like this 6754309809986754354676443356783109804566743 * 19.

We must write this product from direct left to right not right to left.Is there any method to answer any given multiplications

from 2 to 20 tables?

Thanking you,Please reply

Yours fathfully ,

Subramani.k

Guest Apr 13, 2017

#1**+1 **

Dear sir, if the question given like this, 2^n=187072209578355573530071658587684226515959365500928,Find the n value ? Is there any method to find the n value within few seconds?

This one is easily solved by using logs as follows:

Log 2^n= Log (187072209578355573530071658587684226515959365500928)

n x 0.3010299956...... =50.2720092758......

n=50.2720092758..../0.3010299956......

n=167

The second part of your question is vague! But you can also take the logs of both numbers and then ADD them up. And to get your result, raise that sum to power 10. Example: 123 x 456. You can take the logs of both numbers and add them up:2.089905.... + 2.658966...=4.748871....Then raise this number to power 10^4.748871=56,088.

Guest Apr 13, 2017