+118723 $$\\\frac{2}{x^{3/7}}+\frac{5}{x^{2/7}}-\frac{3}{x^{1/7}}=0\\\\
x^{3/7}*\left(\frac{2}{x^{3/7}}+\frac{5}{x^{2/7}}-\frac{3}{x^{1/7}}\right)=x^{3/7}*0\\\\
2+5x^{1/7}-3x^{2/7}=0\\\\
let\;y=x^{1/7}\\\\
2+5y-3y^2=0\\\\
3y^2-5y-1=0\\\\
y=\frac{5\pm\sqrt{25+12}}{6}\\\\
y=\frac{5\pm\sqrt{37}}{6}\\\\
x=y^{1/7}=\left(\frac{5\pm\sqrt{37}}{6}\right)^{1/7}$$
I haven't checked it but I think that is somewhere near correct. 
+118723 $$\\\frac{2}{x^{3/7}}+\frac{5}{x^{2/7}}-\frac{3}{x^{1/7}}=0\\\\
x^{3/7}*\left(\frac{2}{x^{3/7}}+\frac{5}{x^{2/7}}-\frac{3}{x^{1/7}}\right)=x^{3/7}*0\\\\
2+5x^{1/7}-3x^{2/7}=0\\\\
let\;y=x^{1/7}\\\\
2+5y-3y^2=0\\\\
3y^2-5y-1=0\\\\
y=\frac{5\pm\sqrt{25+12}}{6}\\\\
y=\frac{5\pm\sqrt{37}}{6}\\\\
x=y^{1/7}=\left(\frac{5\pm\sqrt{37}}{6}\right)^{1/7}$$
I haven't checked it but I think that is somewhere near correct.
