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Can anyone solve this? Answer: 22

 Mar 14, 2019
edited by dgfgrafgdfge111  Mar 15, 2019
 #1
avatar+6196 
+2

 

\(g(3)=1\\ a+b+c = f(1) = f(g(3)) = \\ 2(3^2) - 5(3) + 19 = 18-15+19 = 22\)

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 Mar 15, 2019
 #2
avatar+935 
+1

Thanks!!!

dgfgrafgdfge111  Mar 16, 2019
 #3
avatar+111438 
+1

f(g(x)  =  f ( x - 2)

 

a(x - 2)^2 + b(x - 2) + c  = 

 

a (x^2 - 4x + 4)  + bx - 2b + c

 

ax^2 - 4ax  + 4a  + bx  -2b + c

 

ax^2 + (b - 4a) x + (4a - 2b + c)     =  2x^2 - 5x + 19

 

a = 2

 

b - 4(2)  = - 5

b = 3

 

4(2) - 2(3) + c = 19

2 + c  = 19

c = 17

 

a + b + c  =   22

 

 

cool cool cool

 Mar 16, 2019
 #4
avatar+935 
0

Thanks!!!!

dgfgrafgdfge111  Mar 16, 2019

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