Can anyone solve this? Answer: 22
g(3)=1a+b+c=f(1)=f(g(3))=2(32)−5(3)+19=18−15+19=22
Thanks!!!
f(g(x) = f ( x - 2)
a(x - 2)^2 + b(x - 2) + c =
a (x^2 - 4x + 4) + bx - 2b + c
ax^2 - 4ax + 4a + bx -2b + c
ax^2 + (b - 4a) x + (4a - 2b + c) = 2x^2 - 5x + 19
a = 2
b - 4(2) = - 5
b = 3
4(2) - 2(3) + c = 19
2 + c = 19
c = 17
a + b + c = 22
Thanks!!!!