We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
68
2
avatar+429 

Can anyone solve this?

 Mar 14, 2019
 #1
avatar+100586 
+3

[ 8(a) + b ] + 5[ a + b]  =  13a + 6b

 

13a + 6b  =  8b + a

 

12a = 2b

 

6a = b

 

a  cannot be an integer > 1   because this would make b at least 12....which is impossible in base 8

 

So...

 

a = 1        and b = 6

 

Proof

 

168  + 5 [ 1 + 6]   =  [  (1)*8  + 6]  + 5*7   =  [ 14 ] + 35  =  49

 

And

 

618   =  6(8) + 1   =  49

 

So

 

N  =  168

 

 

cool cool cool

 Mar 14, 2019
 #2
avatar+429 
0

Oh, I see. I thought we had to add the digits when solving in base 8, so I got really confused. Thanks a lot for your help!!! I like the proof!

dgfgrafgdfge111  Mar 14, 2019
edited by dgfgrafgdfge111  Mar 14, 2019

11 Online Users

avatar