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avatar+411 

Can anyone solve this?

 Mar 14, 2019
 #1
avatar+98061 
+2

[ 8(a) + b ] + 5[ a + b]  =  13a + 6b

 

13a + 6b  =  8b + a

 

12a = 2b

 

6a = b

 

a  cannot be an integer > 1   because this would make b at least 12....which is impossible in base 8

 

So...

 

a = 1        and b = 6

 

Proof

 

168  + 5 [ 1 + 6]   =  [  (1)*8  + 6]  + 5*7   =  [ 14 ] + 35  =  49

 

And

 

618   =  6(8) + 1   =  49

 

So

 

N  =  168

 

 

cool cool cool

 
 Mar 14, 2019
 #2
avatar+411 
-1

Oh, I see. I thought we had to add the digits when solving in base 8, so I got really confused. Thanks a lot for your help!!! I like the proof!

 
dgfgrafgdfge111  Mar 14, 2019
edited by dgfgrafgdfge111  Mar 14, 2019

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