2017 NS 9

Sorry, didn't see that!.

Here's my best attempt

Assume that the only two integers are 1 and 3.......and.....the number of 3s is one more than the number of 1s 

So....

[3(n + 1) + 1(n) ]

______________     <   2.1

        2n + 1

4n + 3  <     4.2n + 2.1

.9  < .2n

9/2 < n

n = 5 

 1 1 1 1 1 3 3 3 3 3 3

We need 11 integers