simplyfy
2a4−a3−6a2−a+2a3(2a−1)−[(2a−1)(3a+2)](2a−1)(a3−3a−2)(2a−1)(a3+1−3a−3)(2a−1)[(a+1)(a2−a+1)−3(a+1)](2a−1)(a+1)[(a2−a+1)−3](2a−1)(a+1)(a2−a−2)(2a−1)(a+1)(a−2)(a+1)
I hope this helped,
Gavin.