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 -2by3 raised to the power of 5

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-2by3 raised to the power of 5

 Jul 11, 2015

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 #1
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$${{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}^{{\mathtt{5}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{32}}}{{\mathtt{243}}}} = -{\mathtt{0.131\: \!687\: \!242\: \!798\: \!353\: \!9}}$$

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 Jul 11, 2015

1+0 Answers

 #1
avatar+33614 
+5
Best Answer

$${{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}^{{\mathtt{5}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{32}}}{{\mathtt{243}}}} = -{\mathtt{0.131\: \!687\: \!242\: \!798\: \!353\: \!9}}$$

.

Alan Jul 11, 2015

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