2KI+Pb(NO3)2⟶PbI2+2KNO3
how many moles of lead(II) iodide (PbI2) are produced from 2.0 mol of potassium iodide (KI)?
2KI+Pb(NO3)2⟶ 1 PbI2+2KNO3 One mole of lead iodide is produced from 2 moles of KI
+37153 Guess I should have noted that the equation is 'balanced' ..... for the solution posted above to be true.
