how to do 2log(3)+log(4)-1/2log(25)?
2log(3)+log(4)-1/2log(25) .... we have
log3^2 + log4 - log25^(1/2) = using alogb = logb^a
log 9 + log 4 - log 5 = using loga + logb - logc = log[(a*b)/c]
log[(9*4) / 5] =
log(36/5) =
about . 857
