2log20 to the power 2 -(log5+log8)

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Guest Nov 11, 2014

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Best Answer

$$\\2log20^2 -(log5+log8)\\
=log400^2-(log40)\\
=log160000-(log40)\\
=log(160000/40)\\
=log(4000)\\
=log1000+log4\\
=3+log2^2\\
=3+2log2$$

Melody Nov 11, 2014

Melody · Answer 1 · 2014-11-11T01:01:34

$$\\2log20^2 -(log5+log8)\\
=log400^2-(log40)\\
=log160000-(log40)\\
=log(160000/40)\\
=log(4000)\\
=log1000+log4\\
=3+log2^2\\
=3+2log2$$

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