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(-2p/q)*(-q)^4*2/5 p2

 Aug 5, 2014

Best Answer 

 #1
avatar+118723 
+5

Is this what you mean?

(-2p/q)*(-q)^4*2/5 p^2

 

 

$$\frac{-2p}{q}*(-q)^4*\frac{2}{5} p^2\\\\
=\frac{-2p}{q}*\frac{q^4}{1}*\frac{2p^2}{5}\\\\
=\frac{-2p}{1}*\frac{q^3}{1}*\frac{2p^2}{5}\\\\
=\frac{-4p^3q^3}{5}\\\\$$

 Aug 5, 2014
 #1
avatar+118723 
+5
Best Answer

Is this what you mean?

(-2p/q)*(-q)^4*2/5 p^2

 

 

$$\frac{-2p}{q}*(-q)^4*\frac{2}{5} p^2\\\\
=\frac{-2p}{q}*\frac{q^4}{1}*\frac{2p^2}{5}\\\\
=\frac{-2p}{1}*\frac{q^3}{1}*\frac{2p^2}{5}\\\\
=\frac{-4p^3q^3}{5}\\\\$$

Melody Aug 5, 2014

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