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$${\mathtt{2}}{w}{\mathtt{\,\small\textbf+\,}}{{\mathtt{v}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{x}} = {\mathtt{y}}$$2w+v^2x=y

 Nov 14, 2014
 #1
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$${\mathtt{2}}{w}{\mathtt{\,\small\textbf+\,}}{{\mathtt{v}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{x}} = {\mathtt{y}}$$^(2w+v^2x=y)

 Nov 14, 2014
 #2
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What about it?

 Nov 15, 2014

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