(2x^2)^3 divide by 4x
(8x^4 * y^5)^2 divide by 2x^3 * y^2
(3a^3 * b^7)^4 divide by 3a^4 * b^16
$$\frac{(2x^2)^3}{4x}\\\\ =\frac{8x^6}{4x}\\\\ =2x^5$$
