2x2-9x-5=0
2x^2 -9x - 5 = 0 factor the trinomial
(2x + 1) (x - 5) = 0
Set each factor to 0 and solve for x
2x + 1 = 0 or x - 5 = 0
subtract 1 from both sides add 5 to both sides
2x = - 1 x = 5
divide both sides by 2
x = -1/2
And those are the two solutions