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2x2-9x-5=0

Guest Apr 3, 2017
 #1
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2x^2 -9x - 5  = 0   factor the trinomial

 

(2x + 1) (x - 5)  = 0

 

Set each factor to 0 and solve for x

 

2x + 1  = 0                                 or              x - 5 = 0

 

subtract 1 from both sides                        add 5 to both sides

 

2x  =  - 1                                                       x =  5

 

divide both sides by 2

 

x =  -1/2      

 

And those are the two solutions

 

 

 

cool cool cool

CPhill  Apr 3, 2017

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