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how do you solve 2x^2+9x=-5

 Dec 28, 2014

Best Answer 

 #1
avatar+128599 
+5

2x^2+9x=-5  add 5 to both sides

2x^2 + 9x + 5 = 0   this won't factor.....using the on site solver to find "x," we have

$${\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}\right)}{{\mathtt{4}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,-\,}}{\mathtt{9}}\right)}{{\mathtt{4}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.850\: \!781\: \!059\: \!358\: \!212\: \!2}}\\
{\mathtt{x}} = -{\mathtt{0.649\: \!218\: \!940\: \!641\: \!787\: \!8}}\\
\end{array} \right\}$$

 

 Dec 28, 2014
 #1
avatar+128599 
+5
Best Answer

2x^2+9x=-5  add 5 to both sides

2x^2 + 9x + 5 = 0   this won't factor.....using the on site solver to find "x," we have

$${\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}\right)}{{\mathtt{4}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,-\,}}{\mathtt{9}}\right)}{{\mathtt{4}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.850\: \!781\: \!059\: \!358\: \!212\: \!2}}\\
{\mathtt{x}} = -{\mathtt{0.649\: \!218\: \!940\: \!641\: \!787\: \!8}}\\
\end{array} \right\}$$

 

CPhill Dec 28, 2014

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